Q59 / 160 · TS EAMCET 2023 (13 May Shift 2) · Mathematics
All possible 5 digit numbers each having 5 distinct digits are formed using digits $1,2,3,5,6,8$. Among them, the number of numbers which are divisible by 3 but not by 6 is
- A120
- B72
- Correct answerC48
- D240
Solution
$1,2,3,5,6,8$
To form number divisible by 3 , they must contain $(2,3,5,6,8)$
and if it is not divisible by 6 , hence it must be odd. $\overline{4} \times \overline{3} \times \overline{2} \times \overline{1} \times \overline{2}=4 ! \times 2$ ways $=48$ ways
Hence, the correct answer is option: 'C'.