Q29 / 120 · NEET 2011 (Mains) · Chemistry

According to the Bohr theory, which of the following transitions in the hydrogen atom will give rise to the least energetic photon?

  • A
    $n=6$ to $n=1$
  • B
    $n=5$ to $n=4$
  • Correct answer
    C
    $n=6$ to $n=5$
  • D
    $n=5$ to $n=3$

Solution

$\because \Delta E \propto\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right]$, where $n_2>n_1$ Energy of photon obtained from the transition $n=6$ to $n=5$ will have least energy.

Hence, the correct answer is option: 'C'.

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