Q20 / 120 · VITEEE 2014 · Chemistry

According to Bohr's theory, the angular momentum for an electron of $3 \mathrm{rd}$ orbit is

Correct answer
A
$3 \hbar$
B
$1.5 \hbar$
C
$9 \hbar$
D
$2 \frac{\hbar}{\pi}$

Solution

Angular momentum, mvr $\begin{array}{l} =\frac{\mathrm{nh}}{2 \pi}=\frac{3 \times \mathrm{h}}{2 \pi}=\frac{1.5 \mathrm{~h}}{\pi} \\ =3 \mathrm{~h}\left[\because \mathrm{h}=\frac{\mathrm{h}}{2 \pi}\right] \end{array}$

Hence, the correct answer is option: 'A'.

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