Q24 / 75 · JEE Main 2025 (2 Apr Shift 1) · Chemistry
According to Bohr's model of hydrogen atom, which of the following statement is incorrect?
- ARadius of \(3^{\text {rd }}\) orbit is nine times larger than that of \(1^{\text {st }}\) orbit.
- BRadius of \(8^{\text {th }}\) orbit is four times larger than that of \(4^{\text {th }}\) orbit.
- Correct answerCRadius of \(6^{\text {th }}\) orbit is three time larger than that of \(4^{\text {th }}\) orbit.
- DRadius of \(4^{\text {th }}\) orbit is four times larger than that of \(2^{\text {nd }}\) orbit.
Solution
\(\mathrm{r} \propto \mathrm{n}^2\)
(1) \(\frac{\mathrm{r}_3}{\mathrm{r}_1}=\frac{9}{1}\)
(2) \(\frac{\mathrm{r}_8}{\mathrm{r}_4}=\frac{64}{16}=4\)
(3) \(\frac{\mathrm{r}_6}{\mathrm{r}_4}=\left(\frac{6}{4}\right)^2=\frac{9}{4}\)
(4) \(\frac{\mathrm{r}_4}{\mathrm{r}_2}=\left(\frac{4}{2}\right)^2=4\)
(1) \(\frac{\mathrm{r}_3}{\mathrm{r}_1}=\frac{9}{1}\)
(2) \(\frac{\mathrm{r}_8}{\mathrm{r}_4}=\frac{64}{16}=4\)
(3) \(\frac{\mathrm{r}_6}{\mathrm{r}_4}=\left(\frac{6}{4}\right)^2=\frac{9}{4}\)
(4) \(\frac{\mathrm{r}_4}{\mathrm{r}_2}=\left(\frac{4}{2}\right)^2=4\)
Hence, the correct answer is option: 'C'.