Q24 / 90 · JEE Main 2021 (18 Mar Shift 2) · Chemistry

A xenon compound $A$ upon partial hydrolysis gives ${XeO}_{2} F_{2}$ . The number of lone pair of electrons present in compound $A$ is ___ (Round off to the Nearest integer)

Correct answer: 19

Solution

$\underset{(A)}{{XeF}_{6}} + \underset{(Limited water)}{2 H_{2} O} ⟶ {XeO}_{2} F_{2} + 4 HF$

Structure of $' A'$

Total l.p. on $(A) = 19$

Hence, the correct answer is 19.

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