Q85 / 90 · JEE Main 2019 (08 Apr Shift 1) · Physics

A wire of length 2L, is made by joining two wires A and B of same length but different radii r and 2r and made of the same material. It is vibrating at a frequency such that the joint of the two wires forms a node. If the number of antinodes in wire A is p and that in B is q then ratio p:q is:
Figure

  • A
     3 :5
  • B
    4 :9
  • C
    1 :4
  • Correct answer
    D
    1 :2

Solution

For rod A, f1=n12lTρA1
For rod B, f2=n22lTρA2
Given f1=f2
n12lTρA1=n22lTρA2      
n12lTρA1=n22lTρ(4A1)      ∵rB=2rAA2=4A1
n1=n22
n1n2=12

Hence, the correct answer is option: 'D'.

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