Q82 / 125 · BITSAT 2010 · Mathematics
A wholesale merchant wants to start the business of cereal with \(₹ 24000\). Wheat is \(₹ 400\) per quintal and rice is \(₹ 600\) per quintal. He has capacity to store 200 quintal cereal. He earns the profit \(₹ 25\) per quintal on wheat and ₹ 40 per quintal on rice. If he store \(\mathrm{x}\) quintal rice and y quintal wheat, then for maximum profit the objective function is
- A\(25 x+40 y\)
- Correct answerB\(40 x+25 y\)
- C\(400 \mathrm{x}+600 \mathrm{y}\)
- D\(\frac{400}{40} \mathrm{x}+\frac{600}{25} \mathrm{y}\)
Solution
For maximum profit, \(z=40 x+25 y\).
Hence, the correct answer is option: 'B'.