Q82 / 125 · BITSAT 2010 · Mathematics

A wholesale merchant wants to start the business of cereal with \(₹ 24000\). Wheat is \(₹ 400\) per quintal and rice is \(₹ 600\) per quintal. He has capacity to store 200 quintal cereal. He earns the profit \(₹ 25\) per quintal on wheat and ₹ 40 per quintal on rice. If he store \(\mathrm{x}\) quintal rice and y quintal wheat, then for maximum profit the objective function is

  • A
    \(25 x+40 y\)
  • Correct answer
    B
    \(40 x+25 y\)
  • C
    \(400 \mathrm{x}+600 \mathrm{y}\)
  • D
    \(\frac{400}{40} \mathrm{x}+\frac{600}{25} \mathrm{y}\)

Solution

For maximum profit, \(z=40 x+25 y\).

Hence, the correct answer is option: 'B'.

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