A wheel has angular acceleration of 3.0 rad / s^2 and an initial angular speed of 2.00 rad / s . In a time of 2 s it has rotated through an angle (in radian) of

Correct answer: (B) 10. θ=ω_0 t+1/2 α t^2 Given, α=3.0 rad / s^2, ω_0=2.0 rad / s, t=2 ~s . Hence, θ=2 × 2+1/2 × 3 ×(2)^2 or θ=4+6=10 rad

Q87 / 160 · JIPMER 2009 · Physics

A wheel has angular acceleration of $3.0 \mathrm{rad} / \mathrm{s}^2$ and an initial angular speed of $2.00 \mathrm{rad} / \mathrm{s}$. In a time of 2 s it has rotated through an angle (in radian) of

A
6
Correct answer
B
10
C
12
D
4

Solution

$\theta=\omega_0 t+\frac{1}{2} \alpha t^2$ Given, $\alpha=3.0 \mathrm{rad} / \mathrm{s}^2, \omega_0=2.0 \mathrm{rad} / \mathrm{s}, t=2 \mathrm{~s}$. Hence, $\quad \theta=2 \times 2+\frac{1}{2} \times 3 \times(2)^2$ or $\theta=4+6=10 \mathrm{rad}$

Hence, the correct answer is option: 'B'.

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