A voltmeter with a resistance $50\times {10}^{\mathrm{3 }}\mathrm{\Omega }$ is used to measure voltage in a circuit. To increase its range to $3$ times, the additional resistance to be put in series is

• A

  $9 \times {10}^6 \mathrm{\Omega }$
• Correct answer
  B

  ${10}^5 \mathrm{\Omega }$
• C

  $1.5 \times {10}^5 \mathrm{\Omega }$
• D

  $9 \times {10}^5 \mathrm{\Omega }$

Hence, the correct answer is option: 'B'.