Q83 / 90 · JEE Main 2012 (19 May Online) · Physics

A $6.0$ volt battery is connected to two light bulbs as shown in figure. Light bulb 1 has resistance 3 ohm while light bulb 2 has resistance $6 \mathrm{ohm}$. Battery has negligible internal resistance. Which bulb will glow brighter? Figure

  • A
    Bulb 1 will glow more first and then its brightness will become less than bulb 2
  • Correct answer
    B
    Bulb 1
  • C
    Bulb 2
  • D
    Both glow equally

Solution

Total resistance $=\frac{6 \times 3}{6+3}=2 \Omega$ Current in circuit $=\frac{6}{2}=3 A$ Therefore current through bulb 1 is $2 \mathrm{~A}$ and bulb 2 is $1 A$. So bulb 1 will glow more.

Hence, the correct answer is option: 'B'.

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