Q90 / 120 · VITEEE 2017 · Physics
A vessel of depth $2 \mathrm{~d} \mathrm{~cm}$ is half filled with a liquid of refractive index $\mu_{1}$ and the upper half with a liquid of refractive index $\mu_{2} .$ The apparent depth of the vessel seen perpendicularly is
- A$\left(\frac{\mu_{1} \mu_{2}}{\mu_{1}+\mu_{2}}\right) \mathrm{d}$
- Correct answerB$\left(\frac{1}{\mu_{1}}+\frac{1}{\mu_{2}}\right) \mathrm{d}$
- C$\left(\frac{1}{\mu_{1}}+\frac{1}{\mu_{2}}\right) 2 \mathrm{~d}$
- D$\left(\frac{1}{\mu_{1} \mu_{2}}\right) 2 \mathrm{~d}$
Solution
Apparent depth $=\mathrm{d} / \mu_{1}+\mathrm{d} / \mu_{2}$.
Hence, the correct answer is option: 'B'.