Q192 / 200 · MHT CET - Medical 2026 (25 April Shift 1) · Physics
A vector $\vec{B}$ is along positive y-axis and its vector product with another vector $\vec{A}$ is zero; then vector $\vec{A}$ could be
- A$5\hat{k}$
- B$5\hat{i}$
- Correct answerC$5\hat{j}$
- D$-5\hat{k}$
Solution
Given that vector $\vec{B}$ is along the positive y-axis, we can write $\vec{B} = B\hat{j}$ where $B > 0$.
The vector product of $\vec{B}$ and $\vec{A}$ is zero, which means $\vec{B} \times \vec{A} = \vec{0}$.
For the cross product of two non-zero vectors to be zero, the vectors must be parallel or anti-parallel to each other. This implies that $\vec{A}$ must also be directed along the y-axis.
Therefore, $\vec{A}$ must be of the form $A\hat{j}$.
Among the given options, $5\hat{j}$ is the only vector along the y-axis.
Answer: $5\hat{j}$
The vector product of $\vec{B}$ and $\vec{A}$ is zero, which means $\vec{B} \times \vec{A} = \vec{0}$.
For the cross product of two non-zero vectors to be zero, the vectors must be parallel or anti-parallel to each other. This implies that $\vec{A}$ must also be directed along the y-axis.
Therefore, $\vec{A}$ must be of the form $A\hat{j}$.
Among the given options, $5\hat{j}$ is the only vector along the y-axis.
Answer: $5\hat{j}$
Hence, the correct answer is option: 'C'.