Q47 / 90 · JEE Main 2013 (09 Apr Online) · Mathematics
A value of $x$ for which $\sin \left(\cot ^{-1}(1+x)\right)=\cos$ $\left(\tan ^{-1} x\right)$, is :
- Correct answerA$-\frac{1}{2}$
- B1
- C0
- D$\frac{1}{2}$
Solution
$\sin \left(\cot ^{-1}(1+x)\right)=\cos \left(\tan ^{-1} x\right)$
$\begin{aligned} & \Rightarrow \operatorname{cosec}^2\left(\cot ^{-1}(1+x)\right)=\sec ^2\left(\tan ^{-1} x\right) \\ & \Rightarrow 1+\left[\cot \left(\cot ^{-1}(1+x)\right)\right]^2 \\ & \Rightarrow=1+\left[\sec \left(\tan ^{-1} x\right)\right]^2 \\ & \Rightarrow(1+x)^2=x^2 \Rightarrow x=-\frac{1}{2}\end{aligned}$
Hence, the correct answer is option: 'A'.