A uniform square plate has a side of length $2 \mathrm{R}$. A circular piece of maximum possible area is cut and removed from one of the quadrants of the plate as shown in the figure. Shift in the centre of mass of the plate is.

• Correct answer
  A

  $\frac{\pi R}{\sqrt{2}(16-\pi)}$
• B

  $\frac{\mathrm{R}}{(16-\pi)}$
• C

  $\frac{\mathrm{R}}{\pi(16-\pi)}$
• D

  $\frac{\mathrm{R} \pi}{(16-\pi)}$

Hence, the correct answer is option: 'A'.