A uniform metal wire of length 'L', mass ' M' and density ' 0 ' is under a tension ' $\mathrm{T}^{\prime}$ '. If the speed of transverse wave along the wire is ' $V^{\prime}$, then area of cross-section of the wire is

• A

  $\frac{\mathrm{V}}{\mathrm{Te}}$
• Correct answer
  B

  $\frac{\mathrm{T}}{\mathrm{V}^{2}} \mathrm{Q}$
• C

  $\frac{\mathrm{T}^{2}}{\mathrm{~V}_{\mathrm{Q}}}$
• D

  $\frac{\mathrm{V}^{2}}{\mathrm{~T} \mathrm{e}}$

Hence, the correct answer is option: 'B'.