Q160 / 160 · AP EAMCET 2019 (22 Apr Shift 1) · Physics

A TV tower has a height \(160 \mathrm{~m}\). Its coverage range is nearly (Earth's radius, \(R_e=6400 \mathrm{~km}\))

  • Correct answer
    A
    \(45255 \mathrm{~m}\)
  • B
    \(55265 \mathrm{~m}\)
  • C
    \(452.55 \mathrm{~km}\)
  • D
    \(552.65 \mathrm{~m}\)

Solution

Given, height of a TV tower, \(h=160 \mathrm{~m}\) Radius of earth, \(R=6400 \mathrm{~km}=6.4 \times 10^6 \mathrm{~m}\) Coverage range of TV tower is given by \(d=\sqrt{2 R h}=\sqrt{2 \times 6.4 \times 10^6 \times 160}=45254.8=45255 \mathrm{~m}\)

Hence, the correct answer is option: 'A'.

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