A transverse wave propagating on a stretched string of linear density 3×10^(-4) kgm^(-1) is represented by the equation y=0.2sin(1.5x+60t) where, x in…

Question

A transverse wave propagating on a stretched string of linear density $3 \times 10^{- 4} {kgm}^{- 1}$ is represented by the equation

$y = 0.2 \sin (1.5 x + 60 t)$

where, $x$ in metres and $t$ is in seconds. The tension in the string (in Newton) is

MARKS Content Team · Accepted Answer

Correct answer: (B) 0.48. Equation of wave, y=0.2sin[1.5x+60t] Comparing with standard equation, we get y=Asin[kx+ωt] k=1.5=(2π)/(λ) and ω=60=(2π)/T ∴ Velocity of wave, v=(ω)/k =60/1.5=40 m s^(-1) Velocity of wave in stretched string, v=√Tm where, m is the linear density, T is tension in the string. So, T=v^2m=(40)^2×3×10^(-4) =0.48 N

A transverse wave propagating on a stretched string of linear density $3 \times 10^{- 4} {kgm}^{- 1}$ is represented by the equation
$y = 0.2 \sin (1.5 x + 60 t)$
where, $x$ in metres and $t$ is in seconds. The tension in the string (in Newton) is

Solution

More Waves and Sound Questions

A transverse wave propagating on a stretched string of linear density 3×10-4 kgm-1 is represented by the equationy=0.2sin(1.5x+60t)where, x in metres and t is in seconds. The tension in the string (in Newton) is

Solution

More Waves and Sound Questions

A transverse wave propagating on a stretched string of linear density $3 \times 10^{- 4} {kgm}^{- 1}$ is represented by the equation
$y = 0.2 \sin (1.5 x + 60 t)$
where, $x$ in metres and $t$ is in seconds. The tension in the string (in Newton) is