Q142 / 197 · NEET 2009 (Mains) · Physics

A transistor is operated in common-emitter configuration at $\mathrm{V}_{\mathrm{C}}=2 \mathrm{~V}$ such that a change in the base current from $100 \mu \mathrm{A}$ to $200 \mu \mathrm{A}$ produces a change in the collector current from $5 \mathrm{~mA}$ to $10 \mathrm{~mA}$. The current gain is :

  • Correct answer
    A
    50
  • B
    75
  • C
    100
  • D
    150

Solution

$$ \begin{aligned} \Delta \mathrm{I}_{\mathrm{B}} & =100 \mu \mathrm{A} \\ \Delta \mathrm{I}_{\mathrm{C}} & =5 \mathrm{~mA} \\ \beta & =\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}=\frac{5 \times 10^{-3}}{100 \times 10^{-6}}=50 \end{aligned} $$

Hence, the correct answer is option: 'A'.

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