A transistor is operated in common emitter configuration at constant collector voltage V_c=1.5 ~V such that a change in the base current from 100 μ A to 150 μ A produces a change in the collector current from 5 mA to 10 mA. The current gain (β) is:-

Correct answer: (D) 100. Current gas =β=(Δ I_C)/(Δ I_B) =((10-5) mA)/((150-100) mA)=frac5 × 10^-350 × 10^-16 =10 C

Q142 / 200 · NEET 2006 · Physics

A transistor is operated in common emitter configuration at constant collector voltage $\mathrm{V}_{\mathrm{c}}=1.5 \mathrm{~V}$ such that a change in the base current from $100 \mu \mathrm{A}$ to $150 \mu \mathrm{A}$ produces a change in the collector current from 5 mA to 10 mA. The current gain $(\beta)$ is:-

A
50
B
67
C
75
Correct answer
D
100

Solution

Current gas $=\beta=\frac{\Delta I_C}{\Delta I_B}$ $$ \begin{aligned} & =\frac{(10-5) \mathrm{mA}}{(150-100) \mathrm{mA}}=\frac{5 \times 10^{-3}}{50 \times 10^{-16}} \\ & =10 \mathrm{C} \end{aligned} $$

Hence, the correct answer is option: 'D'.

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