A train is moving with a speed of 12 m s^(-1) on rails which are 1.5 m apart. To negotiate a curve radius 400 m, the height by which the outer rail…

Question

A train is moving with a speed of 12 m s^(-1) on rails which are 1.5 m apart. To negotiate a curve radius 400 m, the height by which the outer rail should be raised with respect to the inner rail is (Given, g= 10 m s^(-2)):

MARKS Content Team · Accepted Answer

Correct answer: (B) 5.4 cm. For the train, moving along the curved rails, it can be written, with reference to the figure below, that tanθ=v^2Rg ...1 Also, from the above figure, it follows that tanθ=h/1.5 ...2 Equations (1) and (2) imply that h/1.5=v^2Rg⇒h=1.5×(v^2)/Rg=1.5×(12 m s-1^2)/(400 m×10 m s^(-2))=0.054 m=5.4 cm

A train is moving with a speed of $12 m s^{- 1}$ on rails which are $1.5 m$ apart. To negotiate a curve radius $400 m$ , the height by which the outer rail should be raised with respect to the inner rail is (Given, $g =$ $10 m s^{- 2}$ ):

Solution

Relevant Questions

A train is moving with a speed of 12 m s-1 on rails which are 1.5 m apart. To negotiate a curve radius 400 m, the height by which the outer rail should be raised with respect to the inner rail is (Given, g= 10 m s-2):

Solution

Relevant Questions

A train is moving with a speed of $12 m s^{- 1}$ on rails which are $1.5 m$ apart. To negotiate a curve radius $400 m$ , the height by which the outer rail should be raised with respect to the inner rail is (Given, $g =$ $10 m s^{- 2}$ ):