Q77 / 90 · JEE Main 2012 (Offline) · Physics
A thin liquid film formed between a U-shaped wire and a light slider supports a weight of $1.5 \times 10^{-2} \mathrm{~N}$ (see figure). The length of the slider is $30 \mathrm{~cm}$ and its weight negligible. The surface tension of the liquid film is


- A$0.0125 \mathrm{~Nm}^{-1}$
- B$0.1 \mathrm{~Nm}^{-1}$
- C$0.05 \mathrm{~Nm}^{-1}$
- Correct answerD$0.025 \mathrm{~Nm}^{-1}$
Solution
The force of surface tension acting on the slider balances the force due to the weight.
$\begin{array}{ll}
\Rightarrow & \mathrm{F}=2 \mathrm{~T} \ell=\mathrm{w} \\
\Rightarrow & 2 \mathrm{~T}(0.3)=1.5 \times 10^{-2} \\
\Rightarrow & \mathrm{T}=2.5 \times 10^{-2} \mathrm{~N} / \mathrm{m}
\end{array}$


Hence, the correct answer is option: 'D'.