Q142 / 160 · TS EAMCET 2020 (10 Sep Shift 2) · Physics

A telescope has an objective of focal length $100 \mathrm{~cm}$ and an eye-piece of focal length $5 \mathrm{~cm}$. The magnifying power of the telescope is

  • Correct answer
    A
    20
  • B
    500
  • C
    $\frac{1}{20}$
  • D
    105

Solution

Magnification of a telescope for normal setting is $m=\frac{f_o}{f_e}=\frac{100}{5}=20$

Hence, the correct answer is option: 'A'.

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