Q142 / 160 · TS EAMCET 2020 (10 Sep Shift 2) · Physics
A telescope has an objective of focal length $100 \mathrm{~cm}$ and an eye-piece of focal length $5 \mathrm{~cm}$. The magnifying power of the telescope is
- Correct answerA20
- B500
- C$\frac{1}{20}$
- D105
Solution
Magnification of a telescope for normal setting is
$m=\frac{f_o}{f_e}=\frac{100}{5}=20$
Hence, the correct answer is option: 'A'.