Q27 / 150 · MHT CET 2026 (17 April Shift 1) · Chemistry
A system is provided 50 J of heat and work done on the system is 10 J. What is change in internal energy ?
- A$40$ J
- Correct answerB$60$ J
- C$30$ J
- D$50$ J
Solution
According to the first law of thermodynamics:
$\Delta U = q + w$
where $q$ is the heat supplied to the system and $w$ is the work done on the system.
Given:
$q = +50$ J (heat is provided to the system)
$w = +10$ J (work is done on the system)
Substituting the values:
$\Delta U = 50 + 10 = 60$ J
Answer: $60$ J
$\Delta U = q + w$
where $q$ is the heat supplied to the system and $w$ is the work done on the system.
Given:
$q = +50$ J (heat is provided to the system)
$w = +10$ J (work is done on the system)
Substituting the values:
$\Delta U = 50 + 10 = 60$ J
Answer: $60$ J
Hence, the correct answer is option: 'B'.