Q6 / 150 · MHT CET 2026 (11 April Shift 2) · Chemistry
A syringe has a volume of $10.0\ \text{cm}^3$ at a pressure of $1$ atm. If the end is sealed and the plunger is pushed down (constant temperature), what will be the final volume when the pressure becomes $3.5$ atm?
- A$35.0\ \text{cm}^3$
- Correct answerB$2.86\ \text{cm}^3$
- C$0.286\ \text{cm}^3$
- D$3.50\ \text{cm}^3$
Solution
Using Boyle's Law at constant temperature:
$P_1 V_1 = P_2 V_2$
Given $P_1 = 1\ \text{atm}$, $V_1 = 10.0\ \text{cm}^3$, and $P_2 = 3.5\ \text{atm}$.
Substituting the values:
$1 \times 10.0 = 3.5 \times V_2$
$V_2 = \dfrac{10.0}{3.5} = 2.857\ \text{cm}^3$
Rounding to appropriate significant figures, $V_2 = 2.86\ \text{cm}^3$.
Answer: $2.86\ \text{cm}^3$
$P_1 V_1 = P_2 V_2$
Given $P_1 = 1\ \text{atm}$, $V_1 = 10.0\ \text{cm}^3$, and $P_2 = 3.5\ \text{atm}$.
Substituting the values:
$1 \times 10.0 = 3.5 \times V_2$
$V_2 = \dfrac{10.0}{3.5} = 2.857\ \text{cm}^3$
Rounding to appropriate significant figures, $V_2 = 2.86\ \text{cm}^3$.
Answer: $2.86\ \text{cm}^3$
Hence, the correct answer is option: 'B'.