Q44 / 54 · KVPY 2017 (5 Nov SA) · Physics
A student performs an experiment to determine the acceleration due to gravity $\mathrm{g}$. The student throws a steel ball up with initial velocity $u$ and measures the height h travelled by it at different times $t$. The graph the student should plot on a graph paper to readily obtain the value of $g$ is
- A$h$ versust.
- B$\mathrm{h}$ versus $\mathrm{t}^{2}$
- C$h$ versus $\sqrt{t}$.
- Correct answerD$\frac{\mathrm{h}}{\mathrm{t}}$ versust.
Solution
$\begin{array}{l}
\mathrm{h}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2} \\
\mathrm{~h}=\mathrm{ut}-\frac{1}{2} \mathrm{gt}^{2} \\
\frac{\mathrm{h}}{\mathrm{t}}=\mathrm{u}-\frac{1}{2} \mathrm{~g} \mathrm{t} \\
\mathrm{y}=\mathrm{m} \mathrm{x}+\mathrm{c}
\end{array}$
stope will define the value gravity.
Hence, the correct answer is option: 'D'.