Q132 / 180 · NEET 2018 · Physics

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and 25th division of circular scale coincides with reference line. If screw gauge has a zero error of -0.004 cm, the correct diameter of the ball is

  • A
    0.053 cm
  • B
    0.525 cm
  • C
    0.521 cm
  • Correct answer
    D
    0.529 cm

Solution

Diameter of the steel ball = main scale reading + (circular scale reading × Least count) - zero error

=MSR+( CSR×L.C )− zero error

=0.5 cm+25×0.001−( −0.004 )

=0.5+0.025+0.004

=0.529 cm

Hence, the correct answer is option: 'D'.

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