Q38 / 98 · NTA Abhyas (JEE Main) 2020 · Mathematics · Permutation Combination

A student has to answer 10 out of 13 questions in an examination. The number of ways in which he can answer, if he must answer atleast three of the first five questions, is

  • Correct answer
    A
    276
  • B
    600
  • C
    840
  • D
    640

Solution

The possible cases are:Figure
Required number of ways =C53×C87+C54×C86+C55×C85
=5×42×8+5×8×72+1×8×7×63×2
=80+140+56=276

Hence, the correct answer is option: 'A'.

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