Q44 / 117 · NTA Abhyas (JEE Main) 2020 · Physics · Waves and Sound
A string of mass per unit length is clamped at both ends such that one end of the string is at and the other is at . When the string vibrates in fundamental mode, the amplitude of the mid-point of the string is , and tension in the string is , Find the total oscillation energy stored in the string.
- Correct answerA
- B
- C
- D
Solution
The amplitude at a distance x from the origin is given by
consider an element of mass dm and length dx of string at a distance x from the origin
The total energy of this element = its maximum KE
(Because and and it is given that
Hence, the correct answer is option: 'A'.