Q69 / 150 · JEE Main 2006 · Mathematics

A straight line through the point A(3, 4) is such that its intercept between the axes is bisected at A. Its equation is

A
x + y = 7
B
3x − 4y + 7 = 0
Correct answer
C
4x + 3y = 24
D
3x + 4y = 25

Solution

The equation of axes is $x y=0$ $\Rightarrow$ the equation of the line is $\frac{x \cdot 4+y \cdot 3}{2}=12 \Rightarrow 4 x+3 y=24$

Hence, the correct answer is option: 'C'.

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