A straight conductor of length 4 ~m moves at a speed of 10 ~m / s . When the conductor makes on angle of 30^° with the direction of magnetic field of induction of 0.1 ~Wb-m^2 , then induced emf is

Correct answer: (D) 2 ~V. Induced emf is given by e =B v l sin θ =0.1 × 10 < 4 sin 30=2 ~V

Q156 / 160 · AP EAMCET 2012 · Physics

A straight conductor of length $4 \mathrm{~m}$ moves at a speed of $10 \mathrm{~m} / \mathrm{s}$. When the conductor makes on angle of $30^{\circ}$ with the direction of magnetic field of induction of $0.1 \mathrm{~Wb}-\mathrm{m}^2$, then induced emf is

Induced emf is given by $\begin{aligned} e & =B v l \sin \theta \\ & =0.1 \times 10 < 4 \sin 30=2 \mathrm{~V}\end{aligned}$

Hence, the correct answer is option: 'D'.