A straight conductor of length $0.4 \mathrm{m}$ is moving with a speed of $7 {\mathrm{ms}}^{-1}$ perpendicular to the magnetic field of intensity of $0.9 \mathrm{Wb} {\mathrm{m}}^{-2}$. The induced emf across the conductor will be

If a rod of length $l$ is moved with velocity $\overrightarrow{v}$ at an angle $\theta$ to the length of the rod in a filed $\overrightarrow{B}$ which is perpendicular to the plane of motion, the flux linked with the area generated by the motion of rod in time t.
$\varphi =Bl\left(v sin\theta \right)t$
So, $e=\frac{d\varphi }{dt}=Bv l sin\theta$
This will be maximum when

$sin\theta =max=1$
i.e., the rod is moving perpendicular to its length and then
${\left(e\right)}_{max}=Bvl$
$\therefore e=0.9\times 7\times 0.4=2.52 V$