Q184 / 200 · MHT CET - Medical 2026 (26 April Shift 1) · Physics
A step down transformer connected to an a.c. mains of $220$ V is made to operate at $5.5$ V, $44$ W lamp. The current in the primary circuit is (Ignore power losses)
- A$0.22$ A
- B$0.4$ A
- Correct answerC$0.2$ A
- D$0.25$ A
Solution
Given $V_p = 220$ V, $V_s = 5.5$ V, and output power $P_s = 44$ W.
For an ideal transformer, the input power is equal to the output power.
$P_p = P_s$
$V_p I_p = P_s$
$220 \times I_p = 44$
$I_p = \dfrac{44}{220} = 0.2$ A
Answer: $0.2$ A
For an ideal transformer, the input power is equal to the output power.
$P_p = P_s$
$V_p I_p = P_s$
$220 \times I_p = 44$
$I_p = \dfrac{44}{220} = 0.2$ A
Answer: $0.2$ A
Hence, the correct answer is option: 'C'.