Q141 / 160 · AP EAMCET 2018 (24 Apr Shift 2) · Physics

A steel wire of length $1 \mathrm{~m}$, mass $0.1 \mathrm{~kg}$ and uniform area of cross section $10^{-6} \mathrm{~m}^2$ is rigidly fixed at both the ends without any tension. Its temperature is lowered by $20^{\circ} \mathrm{C}$ and transverse waves are set up by plucking the wire at the middle. The frequency of the fundamental mode is $$ \left(\mathrm{Y}=200 \mathrm{GPa}, \alpha=1.21 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1}\right) $$

  • A
    $21 \mathrm{~Hz}$
  • B
    $42 \mathrm{~Hz}$
  • Correct answer
    C
    $11 \mathrm{~Hz}$
  • D
    $22 \mathrm{~Hz}$

Hence, the correct answer is option: 'C'.

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