A steel wire of length $3.2 \mathrm{m}\left(Y_S=2.0\times {10}^{11} \mathrm{N} {\mathrm{m}}^{-2}\right)$ and a copper wire of length $4.4 \mathrm{m} \left(Y_{\mathit{C}}=1.1\times {10}^{11} \mathrm{N} {\mathrm{m}}^{-2}\right)$ , both of radius $1.4 \mathrm{mm}$ are connected end to end. When stretched by a load, the net elongation is found to be $1.4 \mathrm{mm}$. The load applied, in Newton, will be: (Given $\pi =\frac{22}{7}$)

• A

  $360$
• B

  $180$
• C

  $1080$
• Correct answer
  D

  $154$

Hence, the correct answer is option: 'D'.