Q48 / 54 · JEE Advanced 2017 (Paper 1) · Physics

A stationary source emits sound of frequency f0=492 Hz . The sound is reflected by a large car approaching the source with a speed of 2 ms-1 . The reflected signal is received by the source and superposed with the original. What will be the beat frequency of the resulting signal in Hz? (Given that the speed of sound in air is 330 ms-1 and the car reflects the sound at the frequency it has received).

Correct answer: 6

Solution

Frequency of sound as received by large car approaching the source.

f1=C+V0C f0=330+2330492 Hz.

This car now acts as source for reflected sound wave

∴     freflected=f1

Frequency of sound received by source,

f2=CC-V0 freflected=330330-2×f1=330328×332330×492Hz

∴   Beat frequency =f0-f2=332328-1×492 Hz

=6 Hz

Hence, the correct answer is 6.

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