Q157 / 180 · KCET 2025 · Physics

A square loop of side 2 m lies in the $Y-Z$ plane in a region having a magnetic field $\vec{B}=(5 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}-4 \hat{\mathrm{k}}) \mathrm{T}$. The magnitude of magnetic flux through the square loop is

  • Correct answer
    A
    20 Wb
  • B
    12 Wb
  • C
    16 Wb
  • D
    10 Wb

Solution

$\begin{aligned} & \overline{\mathrm{A}}=(2 \times 2) \hat{\mathrm{i}} \quad \text { [as loop is in y-z plane] } \\ & =4 \hat{\mathrm{i}} \\ & \overline{\mathrm{B}}=5 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}-4 \hat{\mathrm{k}} \mathrm{T} \\ & \therefore \phi=\overline{\mathrm{B}} \cdot \overline{\mathrm{A}}=(5 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}-4 \hat{\mathrm{k}}) \cdot 4 \hat{\mathrm{i}} \\ & =20 \mathrm{~Wb}\end{aligned}$

Hence, the correct answer is option: 'A'.

More Magnetic Effects of Current Questions