Q111 / 200 · NEET 2021 · Physics

A spring is stretched by $5 cm$ by a force $10 N$ . The time period of the oscillations when a mass of $2 kg$ is suspended by it is :

A
$0.0628 s$
B
$6.28 s$
Correct answer
C
$0.628 s$
D
$3.14 s$

Solution

Spring force, $F = k x$

Spring constant, $k = \frac{F}{x} = \frac{10}{0.05} = 200 \frac{N}{m}$

Time period, $T = 2 π \sqrt{\frac{m}{k}}$

$T = 2 π \sqrt{\frac{2}{200}} = 0.2 π = 0.628 s$

Hence, the correct answer is option: 'C'.

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