Q75 / 90 · JEE Main 2023 (11 Apr Shift 2) · Physics

A space ship of mass 2×104 kg is launched into a circular orbit close to the earth surface. The additional velocity to be imparted to the space ship in the orbit to overcome the gravitational pull will be (if g=10 m s-2 and radius of earth =6400 km ):

  • A
    11.2(2-1) km s-1
  • Correct answer
    B
    8(2-1) km s-1
  • C
    7.9(2-1) km s-1
  • D
    7.4(2-1) km s-1

Solution

 The orbital velocity of satellite is 

vorb=GMR

The escape velocity is 

vesc=2GMR

Hence, the additional velocity required is 

Δv=vesc-vorb=2GMR-GMR=(2-1)GMR
=(2-1)gR
=(2-1)10×6400×103
=8(2-1) km s-1

Hence, the correct answer is option: 'B'.

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