Q78 / 91 · KVPY 2020 (SB/SX) · Physics

A source simultaneously emitting light at two wavelengths 400nm and 800nm is used in the Young's double slit experiment. If the intensity of light at the slit for each wavelength is I0, then the maximum intensity that can be observed at any point on the screen is

  • A
    I0
  • B
    2I0
  • C
    4I0
  • Correct answer
    D
    8I0

Solution

At central maxima
Due to 400nm=4I0
Due to 800nm=4 T0
Total Intensity =8I0

Hence, the correct answer is option: 'D'.

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