Q77 / 90 · JEE Main 2019 (10 Apr Shift 2) · Physics

A source of sound  S is moving with a velocity of 50 m s-1 towards a stationary observer. The observer measures the frequency of the source as 1000 Hz. What will be the apparent frequency of the source when it is moving away from the observer after crossing him? (Take velocity of sound in air is  350 m s-1 )

  • Correct answer
    A
    750 Hz
  • B
    857 Hz
  • C
    1143 Hz
  • D
    807 Hz

Solution

When source approaches, f1=f0vv-vs
When source recedes, f2=f0vv+vs
⇒ f2f1=v-vsv+vs
⇒f2=1000×350-50350+50 Hz=750 Hz

Hence, the correct answer is option: 'A'.

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