Q245 / 270 · NDA 2023 (Phase 1) · Mathematics
A solution of the differential equation $\left(\frac{d y}{d x}\right)^2-x \frac{d y}{d x}=0$ is
- A$y=2 x$
- B$y=2 x+4$
- C$y=x^2-1$
- Correct answerD$y=\frac{\left(x^2-2\right)}{2}$
Solution
$\left(\frac{d y}{d x}\right)^2-x\left(\frac{d y}{d x}\right)=0$
$\frac{d y}{d x}\left[\frac{d y}{d x}-\right]=$
$\frac{d y}{d x}=0$ or $\frac{d y}{d x}=x$
New $d y=x d x$
$\Rightarrow \int d y=\int x d x$
$y=\frac{x^2}{2}+C \Rightarrow y=\frac{x^2+2 C}{2}$
$y=\frac{x^2}{2}+C \Rightarrow y=\frac{x^2+2 C}{2}$
Comparing with options, $y=\frac{x^2-2}{2}$
Hence, the correct answer is option: 'D'.