Q23 / 90 · JEE Main 2016 (10 Apr Online) · Chemistry

A solid $XY$ kept in an evacuated sealed container undergoes decomposition to form a mixture of gases $X and Y$ at temperature $T$ .
The equilibrium pressure is $10 bar$ in this vessel. $K_{p}$ for this reaction is?

Correct answer
A
$25$
B
$100$
C
$10$
D
$5$

Solution

\begin{matrix} XY & ⇌ & X \\ (S) & (g) \end{matrix} \begin{matrix} + & Y \\ (g) \end{matrix}

P_{eq} = P_{x} + P_{x}

= 10

\Rightarrow P_{x} = 5

K_{p} = (P_{x}) . (P_{y})

= 5 \times 5 = 25

Hence, the correct answer is option: 'A'.

Relevant Questions

Consider the following reactions in which all the reactants and products are present in gaseous state The value of for the equilibrium is:08 Apr, 2026 (E)Law of Mass Action, Equilibrium Constant (Kc and Kp) and its Application
Solid carbon, CaO and CaCO are mixed and allowed to attain equilibrium at T K. atm atm The partial pressure of CO is ________ atm08 Apr, 2026 (E)Law of Mass Action, Equilibrium Constant (Kc and Kp) and its Application
One mole each of He and are taken in a L closed flask and heated to K to establish the following equilibrium. . for this reaction at K is . 06 Apr, 2026 (M)Law of Mass Action, Equilibrium Constant (Kc and Kp) and its Application
In a closed flask at K, one mole of X Y (g) attains equilibrium as given below : At equilibrium, X Y (g) was dissociated and the total press06 Apr, 2026 (E)Law of Mass Action, Equilibrium Constant (Kc and Kp) and its Application
The values of pressure equilibrium constant recorded at different temperatures for the following equilibrium reaction have been given below 05 Apr, 2026 (M)Law of Mass Action, Equilibrium Constant (Kc and Kp) and its Application
The reaction was initiated with the amount ' ' of . At equilibrium it is found that the amount of remaining is at a total pressure of . The 05 Apr, 2026 (E)Law of Mass Action, Equilibrium Constant (Kc and Kp) and its Application