Q7 / 77 · NTA Abhyas (JEE Main) 2020 · Chemistry · Solid State

A solid $XY$ has $NaCl$ structure. If radius of $X^{+}$ is $100 pm .$ What is the radius of $Y^{-}$ ion:

A
$120 pm$
Correct answer
B
$136 .6$ to $241 .6 pm$
C
$136.6 pm$
D
$241.6 pm$

Solution

For

NaCl

like structure. The radius ratio should be

0.414

to

0.732

\frac{r^{+}}{r^{-}} = \frac{100}{r_{m a x}^{-}} = 0.414

\frac{100}{r_{m i n}^{-}} = 0.732

∴ r_{m a x}^{-} = 241.6 p m

∴ r_{min} = 136.6 pm

Hence, the correct answer is option: 'B'.

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