A solid sphere of mass 2 kg is rolling on a frictionless horizontal surface with velocity 6 m s^(-1). It collides on the free end of an ideal spring…

Question

A solid sphere of mass 2 kg is rolling on a frictionless horizontal surface with velocity 6 m s^(-1). It collides on the free end of an ideal spring whose other end is fixed. The maximum compression produced in the spring will be (Force constant of the spring = 36 N m^(-1)).

MARKS Content Team · Accepted Answer

Correct answer: (B) √2.8 m. Kinetic energy of rolling solid sphere =1/2mV^2+1/2Iω^2 =1/2mV^2+1/2×2/5mr^2ω^2 =1/2mV^2+1/5mV^2 =7/10mV^2 The potential energy of the spring on maximum compression x =1/2kx^2 ∴ 1/2kx^2=7/10mV^2 x^2=14/10(mV^2)/k =14/10×(26^2)/36 =2.8 x=√2.8 m

A solid sphere of mass $2 kg$ is rolling on a frictionless horizontal surface with velocity $6 m s^{- 1}$ . It collides on the free end of an ideal spring whose other end is fixed. The maximum compression produced in the spring will be (Force constant of the spring = $36 N m^{- 1}$ ).

Solution

Relevant Questions

A solid sphere of mass 2 kg is rolling on a frictionless horizontal surface with velocity 6 m s-1. It collides on the free end of an ideal spring whose other end is fixed. The maximum compression produced in the spring will be (Force constant of the spring = 36 N m-1).

Solution

Relevant Questions

A solid sphere of mass $2 kg$ is rolling on a frictionless horizontal surface with velocity $6 m s^{- 1}$ . It collides on the free end of an ideal spring whose other end is fixed. The maximum compression produced in the spring will be (Force constant of the spring = $36 N m^{- 1}$ ).