A solid of 2 ~kg mass absorbs 50 ~kJ when its temperature is raised from 20^° C to 70^° C . The specific heat capacity of this solid in unit of J / kg^° C is

Correct answer: (A) 500. Heat absorbed by a solid is given by Δ Q=m s Δ T where, s= specific heat of solid. ∴ s=(Δ Q)/(m · Δ T)=frac50 × 10002 × (70^°-20^° ) C [∵ Δ Q=50 ~kJ=50 × 1000 ~J] =500 ~J ~kg^-1 ° C^-1

Q137 / 160 · TS EAMCET 2020 (10 Sep Shift 2) · Physics

A solid of $2 \mathrm{~kg}$ mass absorbs $50 \mathrm{~kJ}$ when its temperature is raised from $20^{\circ} \mathrm{C}$ to $70^{\circ} \mathrm{C}$. The specific heat capacity of this solid in unit of $\mathrm{J} / \mathrm{kg}{ }^{\circ} \mathrm{C}$ is

Correct answer
A
500
B
1000
C
1500
D
750

Solution

Heat absorbed by a solid is given by $\Delta Q=m s \Delta T$ where, $s=$ specific heat of solid. $\therefore \quad s=\frac{\Delta Q}{m \cdot \Delta T}=\frac{50 \times 1000}{2 \times\left(70^{\circ}-20^{\circ}\right) \mathrm{C}}$ $[\because \Delta Q=50 \mathrm{~kJ}=50 \times 1000 \mathrm{~J}]$ $=500 \mathrm{~J} \mathrm{~kg}^{-1 \circ} \mathrm{C}^{-1}$

Hence, the correct answer is option: 'A'.

A solid of $2 \mathrm{~kg}$ mass absorbs $50 \mathrm{~kJ}$ when its temperature is raised from $20^{\circ} \mathrm{C}$ to $70^{\circ} \mathrm{C}$. The specific heat capacity of this solid in unit of $\mathrm{J} / \mathrm{kg}{ }^{\circ} \mathrm{C}$ is

Solution

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