Q88 / 160 · JIPMER 2010 · Chemistry

A solid $A B$ has the NaCl structure. If radius of cation $A^{+}$is 120 pm , the maximum possible value of the radius of the anion $B^{-}$is

  • A
    240 pm
  • B
    60 pm
  • C
    49.6 pm
  • Correct answer
    D
    290 pm

Solution

For NaCl crystal, Radius of cation/radius of anion $=0.414$ $\begin{aligned} & \frac{r_{A^{+}}}{r_{B^{-}}}=0.414 \\ & r_{B^{-}}=\frac{r_{A^{+}}}{0.414}=\frac{120}{0.414} \\ & =290 \mathrm{pm} \\ & \end{aligned}$

Hence, the correct answer is option: 'D'.

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