Q22 / 160 · TS EAMCET 2018 (05 May Shift 2) · Chemistry

A solid has hcp lattice. Atoms of $Z$ (anions) form hcp lattice. Atoms of $X$ (cations) occupy all the octahedral voids in the lattice. Atoms of $Y$ (cations) occupy half of the tetrahedral voids. What is the molecular formula of the solid?

  • A
    $X_{2 / 3} Y_{1 / 3} Z$
  • Correct answer
    B
    $X Y Z$
  • C
    $X_{1 / 3} Y_{2 / 3} Z$
  • D
    $X Y Z_2$

Solution

Hcp lattice Anions $=Z$, so the total atoms in hcp is $Z$. $X$ occupied octahed voids so, in octahedral voids equivalent to total atoms and $Y$ occupy half of the tetrahedral voids So, $Y$ is equal to total atoms, i.e. $Y$ is. $$ Y=2 \times Z \times \frac{1}{2} $$ So, molecular formula of compounds is $=X Y Z$

Hence, the correct answer is option: 'B'.

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