Q42 / 120 · NEET 2011 (Mains) · Chemistry

A solid compound $X Y$ has $\mathrm{NaCl}$ structure. If the radius of the cation is $100 \mathrm{pm}$, the radius of the anion ( $Y^{-}$) will be

  • A
    $275.1 \mathrm{pm}$
  • B
    $322.5 \mathrm{pm}$
  • Correct answer
    C
    $241.5 \mathrm{pm}$
  • D
    $165.7 \mathrm{pm}$

Solution

Radius ratio of $\mathrm{NaCl}$ like crystal $=\frac{r^{+}}{r^{-}}=0.414$ or $r^{-}=\frac{100}{0.414}=241.5 \mathrm{pm}$

Hence, the correct answer is option: 'C'.

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