Q34 / 120 · VITEEE 2012 · Chemistry
A solid compound $\mathrm{XY}$ has $\mathrm{NaCl}$ structure. If the radius of the cation is $100 \mathrm{pm}$, the radius of the anion $\left(\mathrm{Y}^{-}\right)$will be
- A$275.1 \mathrm{pm}$
- B$241.5 \mathrm{pm}$
- Correct answerC$322.5 \mathrm{pm}$
- D$165.7 \mathrm{pm}$
Solution
Radius ratio of $\mathrm{NaCl}$ like crystal $=\frac{r^{+}}{r^{-}}$
$=0.414$ or $r^{-}=\frac{100}{0.414}=241.5 \mathrm{pm}$
Hence, the correct answer is option: 'C'.