A solid ball of radius 0.2 m and mass 1 kg lying at rest on a smooth horizontal surface is given an instantaneous impulse of 50 N s at point P as…

Question

A solid ball of radius 0.2 m and mass 1 kg lying at rest on a smooth horizontal surface is given an instantaneous impulse of 50 N s at point P as shown. The number of rotations made by the ball about its diameter before hitting the ground is

MARKS Content Team · Accepted Answer

Correct answer: (C) (3125√3)/(2π). Impulse = change in momentum Along vertical V_V=(50cos⁡30°^())/1m/s=25√3 m s^(-1) Along horizontal V_H=(50cos⁡60°)/1m/s=25 m s^(-1) Time of flight T=2V_V/g=5√(3 )s Also ω=(50×0.2)/25mr^2 rad s^(-1) =625 rad s^(-1) 2πn=ω T ⇒n=(ωT)/(2π)=(3125√3)/(2π)

A solid ball of radius $0.2$ $m$ and mass $1$ $kg$ lying at rest on a smooth horizontal surface is given an instantaneous impulse of $50$ $N s$ at point $P$ as shown. The number of rotations made by the ball about its diameter before hitting the ground is

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